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declare @id as varchar(100)
set @id='1,150,45,33'
select rows from table where table.id in (@id)
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行嗎?
以上面這寫法是不行的,不過只要變巧一下
在這之前,先準備好一個叫做SplitWords函數,放心,人家已經寫好了
為了怕連結失效,我也在此Ctl-C / Ctl-V一下
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CREATE FUNCTION SplitWords(@text varchar(8000)) RETURNS @words TABLE ( pos smallint primary key, value varchar(8000) ) AS BEGIN DECLARE @pos smallint, @i smallint, @j smallint, @s varchar(8000) SET @pos = 1 WHILE @pos <= LEN(@text) BEGIN SET @i = CHARINDEX(' ', @text, @pos) SET @j = CHARINDEX(',', @text, @pos) IF @i > 0 OR @j > 0 BEGIN IF @i = 0 OR (@j > 0 AND @j < @i) SET @i = @j IF @i > @pos BEGIN -- @i now holds the earliest delimiter in the string SET @s = SUBSTRING(@text, @pos, @i - @pos) INSERT INTO @words VALUES (@pos, @s) END SET @pos = @i + 1 WHILE @pos < LEN(@text) AND SUBSTRING(@text, @pos, 1) IN (' ', ',') SET @pos = @pos + 1 END ELSE BEGIN INSERT INTO @words VALUES (@pos, SUBSTRING(@text, @pos, LEN(@text) - @pos + 1)) SET @pos = LEN(@text) + 1 END END RETURN END
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有這個好用的函數後,之前的
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declare @id as varchar(100)set @id='1,150,45,33'select * from table1 where table1.id in (@id)----------------------------------------------------改成:----------------------------------------------------declare @id as varchar(100)set @id='1,150,45,33'select * from table1 t1where t1.id in (select value from dbo.SplitWords(@id) )----------------------------------------------------怎樣,好用吧?